Draw five points in the plane a, b, c, e. start at any position, p0, and leapfrog over a to a new position, p1 (so,
a is the midpoint of pop1). then, leapfrog over b, then c, then then e, then a, then b, then c, then then e,
then a again, and so on. how many jumps wil it take to get back to the starting position, p0?

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b