Mathematics
Mathematics, 21.10.2019 18:20, jairus34

Factor 4^12 āˆ’ 1 in two different ways using the identity x^nāˆ’ a^n = (x āˆ’ a)(x^n+ ax^n-1+ a^2x^n-2++ a^n) and the difference of squares identity.

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Factor 4^12 āˆ’ 1 in two different ways using the identity x^nāˆ’ a^n = (x āˆ’ a)(x^n+ ax^n-1+ a^2x^n-2++...

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