An attendance officer in a small school district noticed a trend among the four elementary schools in the district.
this district used an open enrollment policy, which means any student within the district could enroll at any school
in the district. each year, 10% of the students from adams elementary enrolled at davis elementary, and 10% of
the students from davis enrolled at adams. in addition, 10% of the students from brown elementary enrolled at
carson elementary, and 20% of the students from brown enrolled at davis. at carson elementary, about 10% of
students enrolled at brown, and 10% enrolled at davis, while at davis, 10% enrolled at brown, and 20% enrolled at
carson. the officer noted that this year, the enrollment was 490, 250, 300, and 370 at adams, brown, carson, and
davis, respectively.
a. represent the relationship that reflects the annual movement of students among the elementary schools using
a matrix.
b. write an expression that could be used to calculate the attendance one year prior to the year cited by the
attendance officer. find the enrollment for that year.
c. assuming that the trend in attendance continues, write an expression that could be used to calculate the
enrollment two years after the year cited by the attendance officer. find the attendance for that year.
d. interpret the results to part (c) in context.

y=mx+b is the final answer!   : )

c

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!

htrhyjk

step-by-step explanation:

oiluiylkyuk4515kt

u65ku45kuyfr