Write the equation of the line that contains the given point and has the given slope. (12, 5), slope is 0.25

y=0.25x+2

Step-by-step explanation:

Attached is a picture of point-slope form. m=slope

We already have been given the slope 0.25

1) Plug in 0.25 as m in point-slope form:

y-y₁=0.25(x-x₁)

2) Now plug in the points as x₁ and y₁ respectively:

y-5=0.25(x-12)

3) Distribute 0.25 to x and -12:

y-5=0.25x-3

4) Add 5 to both sides:

y=0.25x+2

Footnotes:

- If you are only required to answer in point-slope form, the answer would be y-5=0.25(x-12)

-If you are required to answer in slope intercept form, the answer would be

y=0.25x+2

Let me know if you have any questions :)