At a local college, of the male students are smokers and are non-smokers. of the female students, are smokers and are non-smokers. a male student and a female student from the college are randomly selected for a survey. what is the probability that both are non-smokers?

Our required probability is 0.88.

Step-by-step explanation:

Since we have given that

Number of male students are smokers = 10

Number of male students are non smokers = 490

total number of male students = 500

Number of female students are smokers = 40

Number of female students are non smokers = 363

Total number of female students = 403

Probability that both are non smokers is given by

Hence, our required probability is 0.88.

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

can you rephrase the question ? it is unclear : -)

step-by-step explanation: