Answer oml im begging oml just answee : p

a website password can be four letters long. the letters a, b, c, d, e, f, g, and h are the only letters allowed.

what is the probability that a randomly chosen password starts with d followed by e, and doesn't contain the same letter twice?

enter your answer as a fraction in simplest form

5 ways to select the 1st letter

4 ways to select the 2nd letter

3 ways to select the 3rd letter

2 ways to select the 4th letter

Total # of ways = 5*4*3*2 = 120 passwords

Another way to get the answer 5P4 = 5!/(5-4)!

Step-by-step explanation:

6/20

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)