Apharmacist needs 20 liters of a 2% saline solution. she has a 1% solution and a 5% solution available. how many liters of the 1% solution and how many liters of the 5% solution should she mix to make the 2% solution?

15 liters of 1% solution and 5 liters of 5% solution

Step-by-step explanation:

Let x liters of 1% solution needed and y liters of 5% solution needed to make this mixture.

We can say:

20(0.02) = x(0.01) + y(0.05)

0.4 = 0.01x + 0.05y

Also, we can write:

x + y = 20

x = 20 - y

We can put this into equation 1:

0.4 = 0.01x + 0.05y

0.4 = 0.01(20 - y) + 0.05y

0.4 = 0.2 - 0.01y + 0.05y

0.2 = 0.04y

y = 5 liters

Hence, x = 20 - 5 = 15 liters

We need,

15 liters of 1% solution and 5 liters of 5% solution

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead