Let f(x)=\dfrac{x^2+6x-27}{q(x)}f(x)= q(x) x 2 +6x−27 f, (, x, ), equals, start fraction, x, squared, plus, 6, x, minus, 27, divided by, q, (, x, ), end fraction, where q(x)q(x)q, (, x, )is a polynomial.

Asquare is dilated by a scale factor of 1.25 to create a new square. how does the area of the new square compare with the area of the original square? a)the area of the new square is 1.25 times the area of the original square. b)the area of the new square is 2.50 times the area of the original square. c)the area of the new square is 1.252 times the area of the original square. d)the area of the new square is 1.253 times the area of the original square.

Solve the following: 12(x^2–x–1)+13(x^2–x–1)=25(x^2–x–1) 364x–64x=300x

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