Amarketing executive is studying internet habits of married men and women during the 8am – 10pm time period on weekends ("prime internet time"). based on past data, he has determined that husbands are on the internet 10% of the time during prime internet time. it has also been determined that when the husband is on the internet during prime internet time, 40% of the time the wife is also on the internet. when the husband is not on the internet during prime internet time, the wife is on the internet 20% of the time. if the wife is on the internet during prime internet time, what is the probability that the husband is also on the internet?

Our required probability is 0.18.

Step-by-step explanation:

Since we have given that

Probability that husband is on the internet = 10% = 0.10

Probability that husband is not on the internet = 1-0.10 = 0.9

Probability that wife is on internet given that husband is on internet = 40% = 0.40

Probability that wife is on internet given that husband is not on internet = 20% = 0.20

Probability that wife is on internet is given by

So, Probability that the husband is also on internet given that wife is on internet is given by

Hence, our required probability is 0.18.

the mean and mad

step-by-step explanation:

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b