Pure acid is to be added to a 10% acid solution to obtain 90l of 22% solution. what amount of each solution should be used?

Mix the following to obtain the desired solution:

Assumption:

After mixing, the volume of the final solution is equal to the volume of the 22% solution plus the volume of the pure acid solution.

Step-by-step explanation:

Let the volume of the pure acid required be liters.

The volume of the final solution is given to be 90 liters. If the assumption is true, the volume of the 22% solution has to be equal to liters.

.

Amount of solvent from that liters pure acid solution:

.

Amount of solvent from that liters of 10% acid solution:

.

Solvent from the two solutions, combined:

.

Concentration the mixed solution:

.

This concentration is expected to be equal to

.

In other words,

.

Solve for :

.

That is: liters of the pure acid is required. Another liters of the 22% solution will be required.

idk

step-by-step explanation: