An arrow is launched upward with an initial speed of 100 meters per second (m/s). the equations above describe the constant-acceleration motion of the arrow, where v0 is the initial speed of the arrow, v is the speed of the arrow as it is moving up in the air, h is the height of the arrow above the ground, t is the time elapsed since the arrow was projected upward, and g is the acceleration due to gravity (9.8 m/s2 ). what is the maximum height from the ground the arrow will rise to the nearest meter?

Maximum height, h = 510 meters

Step-by-step explanation:

Initial speed of the arrow,

The equations that describes the constant-acceleration motion of the arrow are as follows :

(speed -time)

(position- time)

(position- speed)

Where

v₀ is the initial speed of the arrow

v is the speed of the arrow as it is moving up in the air

h is height of the arrow above the ground

t is the time elapsed since the arrow was projected upward

g is the acceleration due to gravity

We can use the third equation to find the maximum height from the ground the arrow will rise. At maximum height, v = 0

So,

h = 510.20 meters

or

h = 510 meters

So, the maximum height from the ground the arrow will rise to 510 meters. Hence, this is the required solution.