Calculate the mass of sodium azide (2nan3) required to decompose and produce 1.20 moles of nitrogen.

here is the balanced equation, 2nan3 -> 2na + 3n2

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The answer to your question is:  40.8 g of NaN₃

Step-by-step explanation:

NaN₃ mass = ?

nitrogen = 1.2 moles

Equation

                           2NaN₃      ⇒ 2Na  +  3N2

                          2 moles of NaN₃     3 moles of N₂

                           x                             1.2 moles of N₂

                          x = (1.2 x 2) / 3

                          x = 2.4/ 3

                         x = 0.8 moles of NaN₃

MW NaN₃ = 23 + 28

                = 51 g

                         51 g of NaN₃ 1 mol

                         x                     0.8 mol

                         x = (0.8 x 51) / 1

                        x = 40.8 g of NaN₃

you answer is a

step-by-step explanation:

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.