You work at a bakery, and sell cookies and cupcakes. you can only sell at most 60 baked goods combined. cookies cost $2 each, and a cupcake $3 each. you want to earn at least $100. write a system of linear inequalities to determine how many cookies and cupcakes can be sold.

x+y ≤60

2x+3y ≥ 100

Step-by-step explanation:

Let x represents the number of cookies and y represents the number of cupcakes.

Given : You can only sell at most 60 baked goods combined. Cookies cost $2 each, and a cupcake $3 each. You want to earn at least $100.

Cost of x cookies = 2x

Cost of y cupcakes = 3y

i.e. Inequality For Quantity : x+y ≤60

Inequality For cost : 2x+3y ≥ 100

Now, a system of linear inequalities to determine how many cookies and cupcakes can be sold will be :

x+y ≤60

2x+3y ≥ 100

answer:   the paragraph proof is mentioned below.

step-by-step explanation:

given: in a δxwy where

such that, ∠wzx ≅ ∠yzx and zw≅zy

we have to prove that: segment zx is a perpendicular bisector of segment wy.

prove: since, zw≅zy ⇒ ∠wzy is a supplementary angle.

then, ∠wzy= 180°

⇒∠wzx + ∠yzx = 180° ( because xz divides ∠wzy into two parts)

but, ∠wzx ≅ ∠yzx ( given)

⇒∠wzy+∠wzy=180° ( by substitution)

⇒2∠wzy=180°

⇒∠wzy=90°

⇒∠wzy=∠yzx =90°

therefore, xz⊥wy where wz=zy

⇒zx is a perpendicular bisector of wy.

you'll have to attache the image of the bar graph in order for us to answer : )

step-by-step explanation: