Iwill award

a line segment bk is an angle bisector of δabc. a line km intersects side bc such, that bm = mk. prove: km ∥ ab .

m∠mbk≅m∠ by

<MBK because of the isosceles triangle theorem. If two sides of a triangle are congruent, it is isosceles, so the angles opposite them are also congruent.

Step-by-step explanation:

<MBK is approximately equals to < MKB, by reason of property of an isosceles triangle.

Step-by-step explanation:

In the given triangle, < ABC has a bisector K which divides the angle into two equal parts. Then given that BM = MK,

                < BMK + < CMK = (sum of angles on a straight line)

                < ABC = < CMK (corresponding angles)

Thus, KM ll AB.

Considering the isosceles triangle KBM,

                BM = MK  (given property of the triangle)

Since two sides are equal, then two angles would be equal.

So that,

                <MBK = < MKB (the opposite angles of the sides of an isosceles triangle are equal)

i think it is 18

step-by-step explanation:

we have the parent function given by,

1. the function is translated 5 units to the left.

so, we get,   becomes

2. the function is translated 5 units to the right.

so, we get,   becomes

3. the function is translated 5 units upwards.

so, we get,   becomes

4. the function is translated 5 units downwards.

so, we get,   becomes

5. the function is reflected across x-axis.

so, we get,   becomes

6. the function is reflected across y-axis.

so, we get,   becomes .

step-by-step explanation:

mark brainliest.