Acertain form of cancer is known to be found in women over 60 with probability 0.07. a blood test exists for the detection of the disease, but the test is not infallible. in fact, it is known that 10% of the time the test gives a false negative (i. e., the test incorrectly gives a negative result) and 5% of the time the test gives a false positive (i. e., incorrectly gives a positive result). if a woman over 60 is known to have taken the test and received a favorable (i. e., negative) result, what is the probability that she has the disease?

0.0079 is the probability that woman has cancer when the test were negative.

Step-by-step explanation:

We are given the following information in the question:

Let A be the event when the patient have cancer and B be the event when test result is positive

P(A) = 0.07

Bayes Theorem:

We have to find the probability that she has disease when test were negative that is we have to find:

Putting all the values in the above formula, we have,

Thus. 0.0079 is the probability that woman has cancer when the test were negative.

any options?

step-by-step explanation:

2(2x + 3) = -4 + 2(2x + 5)

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 6

4x - 6 + 6 = 4x - 6 + 6

4x = 4x

x = x

unlimited solutions.