Identify the distance, to the nearest tenth, between c(−7,−9) and j(6,2).

The answer is 17.02, to the nearest tenth is 17.

Step-by-step explanation:

Under the radical, that us take the square root of the following sum:

(Jx - Cx )^2 + (Jy - Cy)^2

Substitute in the values:

(6 - (-7))^2 + (2 - (-9))^2 =

This becomes:

(6+7)^2 + (2 + 9)^2 =

13^2 + 11^2 =

169 + 121 =

Sqrt 290 =

17.029 = To the nearest 10th is 17

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )