The function g(x) = 8x2 – 48x + 65 written in vertex form is g(x) = 8(x – 3)2 – 7. what is the vertex of g(x)?
(–3, –7)
(3, –7)
(24, –7)
(–24, –7)

The answer is (3, -7). If the function is written in the form y = a(x – h)^2 + k, the vertex will be (h, k). Let's write the function 8x^2 – 48x + 65 in the form of a(x – h)^2 + k. g(x) = 8x^2 – 48x + 65. g(x) = 8x^2 – 48x + 72 - 72 + 65. g(x) = (8x^2 – 48x + 72) - 7. g(x) = (8 * x^2 – 8 * 6x + 8 * 9) - 7. g(x) = 8(x^2 - 6x + 9) - 7. g(x) = 8(x - 3)^2 - 7. The function is now in the form a(x – h)^2 + k, where a = 8, h = 3, and k = -7. Thus, the vertex is (3, -7).

The answer is 1 because you have to flip the sign when dividing by negative number and 3