Solve for b by elimination 2a+3b=12
5a-b=13

2a+3b=12

               b=(12-2a)/3

5a-b=13

b= -13+5a

Step-by-step explanation:

1) 2a+3b=12

-2a        -2a

3b=12-2a

/3         /3

b= (12-2a)/3

2) 5a-b=13

   -5a     -5a

-b=13-5a    

*-1   *-1   -b= 13(-1)-5a(-1) *you'd multiply by -1 to cancel out the negative on b*

b= -13+5a

whole numbers.

step-by-step explanation:

we are given the average monthly rainfall (in millimeters) model r(m) for the years 1900-2009 as a function of the month number m.

as we can see m is taken for the number of months for years 1900-2009.

we know that number of months can't be a negative number or decimal number or a fraction.

so, the number of months could be only positive whole numbers.

therefore, whole numbers is more appropriate for the domain of r.

step-by-step explanation: the answer for wha if rt is 10 centimeters long, and wha is st? it’s 6