What is the axis of symmetry of h(x) = 5x2 + 40x + 64?
x = −16
x = −4
x = 4
x = 16

The graph of a quadratic function is a parabola. The axis of symmetry of a parabola is a vertical line that divides the parabola into two similar halves. The axis of symmetry always passes through the vertex of the parabola . The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola. For the function h(x) = 5x^2 + 40x + 64 we write it in vertex form as follows: h(x) = 5(x^2 + 8x) + 64 h(x) = 5(x^2 + 8x + 16) + 64 - 5(16) h(x) = 5(x + 4)^2 + 64 - 80 h(x) = 5(x - (-4))^2 - 16 Thus the vertex is given by (h, k) = (-4, -16) Therefore, the axis of symmetry of h(x) = 5x^2 + 40x + 64 is the line x = -4

2160ft^3 i think you could use a formala to you out with this in the future