Assume that the population of the world in 2010 was 6.9billion and is growing at the rate of 1.1% a year. a) set up a recurrence relation for the population of theworld n years after 2010. b) find an explicit formula for the population of theworld n years after 2010. c) what will the population of the world be in 2030? 21. a factory makes custom sports cars at an increasing rate

a)

If we call P(n) the population n years after 2010, the recurrence relation for the population of the world n years after 2010 would be

P(0) = 6.9 billion

P(n) = P(n-1)*(1.011)

b)

c)

Step-by-step explanation:

a)

If the growing rate is 1.1% in the year 2011 was

6.9 + 1.1% of 6.9 = 6.9 + 6.9*(0.011) = 6.9*(1.011)

In the year 2012, the new population was

6.9*(1.011) + 1.1% of 6.9*(1.011)

= 6.9*(1.011) + 6.9*(1.011)*(0.011) = 6.9*(1.011)*(1+0.011)

= 6.9*(1.011)*(1.011) =

Similarly, we can see that the population in 2013 was

If we call P(n) the population n years after 2010, the recurrence relation for the population of theworld n years after 2010 would be

P(0) = 6.9 billion

P(n) = P(n-1)*(1.011)

b)

In the year n after 2010, the population would be

c)

The population of the world in 2030, according to the formula, will be P(20)

72 fudge and 75 toffee

step-by-step explanation:

i hope this : )

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841