Consider the following information about travelers on vacation: 40% check work email, 30% use a cell phone to stay connected to work, 25% bring a laptop with them, 16% both check work email and use a cell phone to stay connected, and 49% neither check work email nor use a cell phone to stay connected nor bring a laptop. in addition, 88 out of every 100 who bring a laptop also check work email, and 70 out of every 100 who use a cell phone to stay connected also bring a laptop. a) what is the probability that a randomly selected traveler whochecks work email also uses a cell phone to stay connected?

There is a 40% probability that a randomly selected traveler whochecks work email also uses a cell phone to stay connected.

Step-by-step explanation:

a) What is the probability that a randomly selected traveler whochecks work email also uses a cell phone to stay connected?

The problem states that 40% of the travelers on vacation check work email. And 16% of them check both work email and use a cell phone.

So, the probability is the division of those who use both email and cellphone by those who use email.

There is a 40% probability that a randomly selected traveler whochecks work email also uses a cell phone to stay connected.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2