Assume a and b are both integers and a > 0. define a remainder after the division of b by a to be a value r such that r ⥠0, r < a, and there exists an integer q for which b = aq + r. a) prove uniqueness. that is, if r1 and r2 are both remainders after the division of b by a, then r1 = r2. y

r1=r2

Step-by-step explanation:

Initially,let´s assume there are two remainders r1, and r2. This must fit the following equations:

b=a.q + r1   (equation 1)

b=a.q + r2  (equation 2)

Because we have the same variable b in both equations, we can make equal both expressions, and solving:

a.q + r1 = a.q +r2

      - r2=      -r2

a.q + r1 - r2 = a.q + 0

a. q + r1 - r2 = a.q

-a.q             = - a.q

0 + r1 - r2 = 0

r1 - r2 = 0

   +r2 = r2

r1 + 0 = r2

r1 = r2 And this is what we want to proof.

i need a picure

step-by-step explanation:

square root of 36/6 = 2.449489743

square root of 16/6 = 1.632993162

square root of 6 = 2.449489743

the answer is square root of 16/6 because the square root of 36/6 is the same answer as square root of 6 = 2.449489743