Need

a stadium has 50,000 seats. seats sell for $30 in section a, $24 in section b, and $18 in section c. the number of seats in section a equals the total number of seats in sections b and c. suppose the stadium takes in $1,289,400 from each sold-out event. how many seats does each section hold?

Step-by-step explanation:

Section A comprises half the seats, so contains 26,500 seats.

The revenue from those is ...

  $28×26,500 = $742,000

so the revenue from the remaining seats is ...

  $1,118,800 -742,000 = $376,800

An equation for that can be written using "b" for the number of section B seats:

  16b +12(26,500 -b) = 376,800

  4b + 318,000 = 376,800

  b = (376,800 -318,000)/4 = 14,700

Then the remaining number of seats is the number in section C:

  26,500 -14,700 = 11,800

There are 26,500 seats in Section A, 14,700 seats in Section B, and 11,800 seats in Section C.

13.33%

say 50 oranges, then 100 apples

80 are red, 20 are yellow

total fruit = 150

20chances out of 150 for yellow

20/150 = 13.33%

5x+40

5(x + 8)

7x - 49

7(x - 7)

18x + 9

9(2x + 1)

15x - 10

5(3x - 2)

step-by-step explanation:

for number one all you have to do is factor 5 out of 5x + 40

for number 2 factor 7 out of 7x - 49

for number three factor 9 out of 18x + 9

for number four factor 5 out of 15x - 10