In the figure, cd = ef and ab = ce. complete the statements to prove that ab = df. cd + de = ef + de by the property of equality. ce = cd + de and df = ef + de by . ce = df by the property of equality. given, ab = ce and ce = df implies ab = df by the property of equality.

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

what is the original number? you forgot to add it.

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