The manager of a school bookstore has found four different companies from which she may order book bags. the algebraic rules shown for each company represent the cost of placing a book bag order, c, based on the number of book bags purchased, b

company a: c = 12b
company b: c = 8.25b + 55
company c: 8b + 100
company d: c = 15b - 55

write a situation for each algebraic rule, if possible.

company a:
company b:
company c:
company d:

We are going to set a few rules for this one:

c = the cost of placing a book bag order. (Variable already set).

b = the number of book bags purchased, and the set number of book bags purchased will be 50. (Just an example).

Now that that's set, Let's solve!

Company A:

c = 12b              [substitue in values]

c = 12(50)          [solve]

c = 600

So the cost of the book bags for Company A is $600.

Company B:

c = 8.25b + 55           [substitute in values]

c = 8.25(50) + 55       [solve]

c = 412 + 55               [solve]

c = 467.50

So the cost of the book bags for Company B is $467.50.

Company C:

c = 8b + 100               [substitute in values]

c =   8(50) + 100         [solve]

c = 400 + 100             [solve]

c = 500

So the cost of the book bags for Company C is $500.

Company D:

c = 15b - 55              [substitute in values]

c = 15(50) - 55          [solve]

c = 750 - 55              [solve]

c = 695

So the cost of the book bags for Company D is $695.

The least expensive company was Company B, and the most expensive company was Company D. (Not that you were asking).

I hope this helps!

wow i needed help with this too

Step-by-step explanation:

b. 18

step-by-step explanation:

so the equation for this is:

ab^2=ac⋅ad

ab being the top length of 6 and ac being the length of 2 and ad being the length of x. let's plug into the equation:

6^2 = 2x

now lets just solve for x:

36 = 2x

18 = x

i hope that !