Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gender of any other children. find the probability of exactly five girls in ten births.

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The probability is 0.2461

or 24.6% to the nearest tenth.

Step-by-step explanation:

This is a Binomial Probability Distribution.

The formula for  B(r; n,p) = nCr p^r (1 - p)^(n-r)   where r = number of successes, p = probability of a success.

Here, r = 5 , n = 10 and p = 1/2.

So  for 5 girls in 10 births it is

10C5 (1/2)^5 (1 - 1/2)^(10-5)

= 252 * 1/32 * 1/32

= 0.2461.

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2