If cos θ = square root 2 over 2 and 3 pi over 2 < θ < 2π, what are the values of sin θ and tan θ? sin θ = square root 2 over 2; tan θ = −1 sin θ = negative square root 2 over 2; tan θ = 1 sin θ = square root 2 over 2; tan θ = negative square root 2 sin θ = negative square root 2 over 2; tan θ = −1

b) 36

step-by-step explanation:

18 times 2 is 36

126.66 m²

step-by-step explanation:

the pertinent area formula is a = πr², where r is the radius.

here, a = π(6.35 m)² = 40.32π, or approximately 126.66 m²

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204