Mr. ward and mr. heskey are racing toy cars and mr. heskey wants to give mr. ward an 8 ft head start because his car is 2 seconds slower. mr. ward's car travels 4 feet per second and mr. he's key's car travels 6 ft per second.

which inequality could be used to determine after how many seconds, 's mr. heskey's car will be head of mr. ward's car?

show how you got the answer.

  F.  6s > 4s +8

Step-by-step explanation:

From a reference point at the beginning of the track, Ward's car will be located 4s+8 feet down the track after s seconds. That is, it starts 8 feet down the track, and increases its distance by 4 feet every second.

From the same reference point, Heskey's car will be located 6s feet down the track after s seconds. Its distance starts from zero and is increasing at the rate of 6 feet every second.

For Heskey's distance to exceed Ward's distance you want ...

  6s > 4s +8 . . . . . . matches choice F

damm bro the struggle

step-by-step explanation:

the answer is 150.6

step-by-step explanation:

you multiply .02 by 30 and get .6.

and then you multiply 5.00 by 30 and get 150.

hope this !