If the length of a paddock is 2m more than its width and the area is 48m^2, find the length and width of the paddock.

➷  Let the width be 'x' and the length be 'x + 2'

Area = l x w

Substitute the values in:

48 = x(x + 2)

48 = x^2 + 2x

Use trial and error [it'll only take a few turns] to get the value for x

x = 6

x + 2 = 8

Thus, the length of the paddock is 8m and the width is 6m.

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ANSWER:  

The length and width of the paddock are 8, 6.

SOLUTION:

Given, length of a paddock is 2m more than its width.

Let the length of paddock be “x”

Then the width of paddock becomes x – 2.

Also given that, area of paddock is 48

area = 48

In general, paddocks are rectangular in shape. Area of rectangle is given by

area of rectangle = length breadth

Length breadth = 48  

x(x – 2) = 48

we can write 48 as product of 8 and 6

x(x – 2) = 8 x 6    

Now, by comparing on both sides, We can say that

x = 8 and x -2 = 6

Finally , the value of x is 8 and x - 2 is 6

Hence, the length and width of the paddock are 8, 6.

the least common denominator is 40

triangle and cube

step-by-step explanation: