Two hikers are 44 miles apart and walking toward each other. they meet in 10 hours. find the rate of each hiker if one hiker walks 2.2 mph faster than the other.

The rate of each hiker is 1 miles per hour and 3.2 miles per hour.

Solution:

Let the rate of the hiker 1 be ‘x’ and the rate of the hiker 2 be (x+2.2). We have to find out the rate of each hiker if they meet each other in 10 hours

We know,

Distance = speed × time.

In the question it is given that the distance is 44 miles.

Using the equation we will try to find out the rate of each hiker.

44 = (x)10 + (x+2.2)10

44 = 10x + 10x + 22

44-22 = 20x

20 = 20x

x = 1

Therefore the rate of hiker 1 = 1 miles per hour and the rate of hiker 2 = (1+2.2) = 3.2 miles per hour

step-by-step explanation:

y=mx+b