There are 236 juniors and seniors in mr. jay's math class. there are 4 fewer juniors than twice the number of seniors. how many juniors are in his class?

question 17 options:

118

80

156

116

64

156

Step-by-step explanation:

Let number of juniors be j and number of seniors be s

Thus, we can write:

236 juniors and seniors in Mr. Jay's math class:

j + s = 236

Also

There are 4 fewer juniors than twice the number of seniors:

j = 2s - 4

Now putting equation 2 into 1, we can solve for s:

j + s = 236

2s - 4 + s = 236

3s = 240

s = 80

Hence, juniors is:

j = 2s - 4

j = 2(80) - 4

j = 156

There are 156 juniors

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

i don't know

step-by-step explanation: