What is an equation of the line that passes through (6,-1) and is parallel to the line x-3y = 3

a=-3

Step-by-step explanation:

find the equation of the line parallel to the line x−3y=3 passing through the point (6,−1).

The equation of the line in the slope-intercept form is y=x3−1.

The slope of the parallel line is the same: m=13.

So, the equation of the parallel line is y=x3+a.

To find a, we use the fact that the line should pass through the given point: −1=(13)⋅(6)+a.

Thus, a=−3.

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)

the reporter's right

step-by-step explanation:

1/4 = .25 / 25%