18 pts! from the equation below, identify the slope and a point on the line. y−3=−2(x+1)

ANSWER:  

The slope of the given equation is -2 and a point on the given line is (-1, 3)

SOLUTION:

Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)

We need to find the slope of the given equation and a point through which the given line passes.

Given equation is in the form of point slope form  .i.e --- eqn 2

where,"m" is the slope of the line

is point on that line.

Now, by comparing (1) and (2)

m = -2

so, the slope of the given equation is -2  and a point on the given line is (-1, 3)

slope: − 2

y-intercept: ( 0 , 1 )

x y 0 1 1 − 1

Step-by-step explanation: Graph the line using the slope and y-intercept, or two points.

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x

idk

step-by-step explanation: