Mathematics

Mathematics, 10.10.2019 23:30, stodd9503

What is the simplified form of 3 startroot 135 endroot?

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Mathematics, 20.09.2019 23:30, torresfatima20pa6p1r

What is the positive solution to the equation 0 = –x2 + 2x + 1? quadratic formula: x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction –2 + startroot 2 endroot 2 – startroot 2 endroot 1 + startroot 2 endroot –1 + startroot 2 endroot

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Mathematics, 08.10.2019 22:00, amariyanumber474

What is the positive solution to the equation 0 = –x2 + 2x + 1? quadratic formula: x = startfraction negative b plus or minus startroot b squared minus 4 a c endroot over 2 a endfraction –2 + startroot 2 endroot 2 – startroot 2 endroot 1 + startroot 2 endroot –1 + startroot 2 endroot

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Mathematics, 05.12.2019 19:31, dennisedemirovic20

Which are the roots of the quadratic function f(q) = q2 – 125? select two options. q = 55 startroot 5 endroot q = -5negative 5 startroot 5 endroot q = 33 startroot 5 endroot q = -3negative 3 startroot 5 endroot q = 2525 startroot 5 endroot

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Mathematics, 10.12.2019 06:31, lin550

Marika solved the equation (6x + 15)2 + 24 = 0. her work is below. 1. (6x + 15)2 = –24 2. startroot (6 + 15) squared endroot = startroot negative 24 endroot 3. 6x + 15 = negative 2 startroot 6 endroot 4. 6x = negative 2 startroot 6 endroot – 15 5. x = startfraction negative 2 startroot 6 endroot minus 15 over 6 endfraction analyze marika’s steps. which statement is true about her work? in step 2, marika should have simplified startroot negative 24 endroot to be 4 startroot negative 6 endroot. there are no real solutions to this equation because the square root of a negative number is not a real number. there should be two real solutions to this equation because startroot negative 24 endroot = plus or minus 2 startroot 6 endroot. marika correctly solved this equation.

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