The proof that δefg ≅ δjhg is shown.
given: g is the midpoint of hf, ef ∥ hj, and ef ≅...
Mathematics, 10.10.2019 21:20, bryanmcmillianjr
The proof that δefg ≅ δjhg is shown.
given: g is the midpoint of hf, ef ∥ hj, and ef ≅ hj.
prove: δefg ≅ δjhg
triangles e f g and j h g share common point g.
statement
reason
1. g is the midpoint of hf 1. given
2. fg ≅ hg 2. def. of midpoint
3. ef ∥ hj 3. given
4. ? 4. alt. int. angles are congruent
5. ef ≅ hj 5. given
6. δefg ≅ δjhg 6. sas
what is the missing statement in the proof?
∠feg ≅ ∠hjg
∠gfe ≅ ∠ghj
∠egf ≅ ∠jgh
∠gef ≅ ∠jhg
Answers: 1
Mathematics, 21.06.2019 17:30, ahnagoede2768
Thelime contains the point(-3,0) and parallel x-3y=3( show all work)
Answers: 3
Mathematics, 21.06.2019 20:30, nosugh
If m∠abc = 70°, what is m∠abd? justify your reasoning. using the addition property of equality, 40 + 70 = 110, so m∠abd = 110°. using the subtraction property of equality, 70 − 30 = 40, so m∠abd = 30°. using the angle addition postulate, 40 + m∠abd = 70. so, m∠abd = 30° using the subtraction property of equality. using the angle addition postulate, 40 + 70 = m∠abd. so, m∠abd = 110° using the addition property of equality.
Answers: 2
Mathematics, 17.02.2022 01:00
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