At a concession stand, seve hot dog (x )hot dog(s) and four hamburger (x )hamburger(s) cost $15.75; four hot dog (x )hot dog(s) and seven hamburger (x )hamburger(s) cost $17.2517.25. find the cost of one hot dog and the cost of one hamburger.

Cost of one hot dog: $1.39 (rounded to the nearest hundredth)

Cost of one hambuger: $1.51 (rounded to the nearest hundredth)

Step-by-step explanation:

Let x and y be the cost of one hot dog and the cost of one hamburger, respectively. With the information given, a system of equations is obtained:

There are a lot of methods to solve a system like this, let's try the substitution method:

The first step is solving one of the equation for one of the variables, let's solve  x for the first equation:

Then, this value is substituted in the second equation and solved for the other variable:

Finally, the value of y is substituted in any of the equations and solved for x:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %

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