Afactory produces 90 packages of mixed nuts in 1 min. a quality control manager selected 8 of these 90 packages at random and then counted the number of nuts in each package. the manager recorded the results.
31, 31, 32, 33, 35, 35, 35, 36
what is the estimated median number of nuts in all 90 packages?

Data set:

31, 31, 32, 33, 35, 35, 35, 36

Median is the middle value of the data set.

Since there is 8 numbers involved, the median is the average of the 4th and 5th number.

(33 + 35)/2 = 68/2 = 34

The median is 34.

38+105= 143, 39+104=143, and you will find then adding the numbers on opposite sides, moving inwards yields the answer 138 every time. because of this, you’re going to multiply 138 times the number of pairs, which is 34. therefore, 34*138= 4692(i’m sorry if it’s the wrong numbers, but it’s the right concept)