Mathematics, 10.10.2019 00:00, bcarri4073

Alarge operator of timeshare complexes requires anyone interested in making a purchase to first visit the site of interest. historical data indicates that 20% of all potential purchasers select a day visit, 50% choose a one-night visit, and 30% opt for a two-night visit. in addition, 40% of day visitors ultimately make a purchase, 30% of one-night visitors buy a unit, and 50% of those visiting for two nights decide to buy. suppose a visitor is randomly selected and is found to have made a purchase. how likely is it that this person made a day visit? (round your answer to three decimal places.) how likely is it that this person made a one-night visit? (round your answer to three decimal places.) how likely is it that this person made a two-night visit? (round your answer to three decimal places.)

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answered: goldenarrow

There is a 21.053% probability that this person made a day visit.

There is a 39.474% probability that this person made a one night visit.

There is a 39.474% probability that this person made a two night visit.

Step-by-step explanation:

We have these following percentages

20% select a day visit

50% select a one-night visit

30% select a two-night visit

40% of the day visitors make a purchase

30% of one night visitors make a purchase

50% of two night visitors make a purchase

The first step to solve this problem is finding the probability that a randomly selected visitor makes a purchase. So:

P = 0.2(0.4) + 0.5(0.3) + 0.3(0.5) = 0.38

There is a 38% probability that a randomly selected visitor makes a purchase.

Now, as for the questions, we can formulate them as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

$P = \frac{P(B).P(A/B)}{P(A)}$

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

Suppose a visitor is randomly selected and is found to have made a purchase.

How likely is it that this person made a day visit?

What is the probability that this person made a day visit, given that she made a purchase?

P(B) is the probability that the person made a day visit. So P(B) = 0.20

P(A/B) is the probability that the person who made a day visit made a purchase. So P(A/B) = 0.4

P(A) is the probability that the person made a purchase. So P(A) = 0.38

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.4*0.2}{0.38} = 0.21053$

There is a 21.053% probability that this person made a day visit.

How likely is it that this person made a one-night visit?

What is the probability that this person made a one night visit, given that she made a purchase?

P(B) is the probability that the person made a one night visit. So P(B) = 0.50

P(A/B) is the probability that the person who made a one night visit made a purchase. So P(A/B) = 0.3

P(A) is the probability that the person made a purchase. So P(A) = 0.38

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.5*0.3}{0.38} = 0.39474$

There is a 39.474% probability that this person made a one night visit.

How likely is it that this person made a two-night visit?

What is the probability that this person made a two night visit, given that she made a purchase?

P(B) is the probability that the person made a two night visit. So P(B) = 0.30

P(A/B) is the probability that the person who made a two night visit made a purchase. So P(A/B) = 0.5

P(A) is the probability that the person made a purchase. So P(A) = 0.38

$P = \frac{P(B).P(A/B)}{P(A)} = \frac{0.3*0.5}{0.38} = 0.39474$

There is a 39.474% probability that this person made a two night visit.

answered: Guest

answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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answers

rauschg

rauschg · hand

know the answer? add it here!

step-by-step explanation:

answered: Guest

the correct answer would be:

220 centimeters

to get this you can use the pythagorean theorem

hope this

step-by-step explanation: