R--> 2 p. initially you start off with 0.5 m reactants and let the reaction run to equilibrium and calculate the equilibrium constant, k, value. what happens to that value if you run the reaction to equilibrium again at the same temperature but double the initial concentration of the reactants to 1.0 m?

K still the same value

Step-by-step explanation:

given a reaction aA+bB<->cC+dD the constant K is defined as:

K is a constant so it won't change the value. Instead, the values of C and D are going to change.  The position of equilibrium moves because of the need to keep a constant value for the equilibrium constant.

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500