Mathematics, 09.10.2019 23:00, simrankaurdhatt

Which statement about the scatterplot is true? the point (2, 10) shows that there is no relationship between the packing time and the number of boxes. although (2, 10) is an extreme value, it should be part of the description of the relationship between packing time and number of boxes. including the point (2, 10) could cause the description of the data set to be understated. including the point (2, 10) could cause the description of the data set to be overstated.

Answers: 2

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Answers

answered: Guest

d. 8

step-by-step explanation:

the given radical expression is:

$\sqrt{16}\times \sqrt{4}$

we can rewrite this as:

$(16)^{\frac{1}{2}\times (4)^{\frac{1}{2}$

we express as square numbers to get;

$(4^2)^{\frac{1}{2}\times (2^2)^{\frac{1}{2}$

the exponents will now cancel out to give.

$4\times2=8$

the correct answer is d

What is the value of the radical expression shown below

answered: Guest

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

answered: Guest

answer:

given the linear inequality : $x-2y\geq -12$

add 2y to both sides we get;

$x-2y+2y\geq -12+2y$

simplify:

$x\geq -12+2y$

add 12 to both sides of an equation;

$x+12\geq -12+2y+12$

simplify:

$x+12\geq 2y$

divide both sides by 2 we get;

$\frac{x}{2} + 6 \geq y$

$y\leq \frac{x}{2} + 6$

the related equation for the inequality equation [1] is;

$y =\frac{x}{2} +6$

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

$y =\frac{0}{2} +6$

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

$0 =\frac{x}{2} +6$

subtract 6 from both sides we get

$0-6 =\frac{x}{2} +6-6$

$-6 =\frac{x}{2}$

multiply both sides by 2 we get;

$-6 \times 2=x$

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.

answered: Guest

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation:

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Which statement about the scatterplot is true? the point (2, 10) shows that there is no relationshi...