Use the information below for questions 5 - 11. let x denote the number of telephone lines in use at an online business. suppose there are 6 lines and p(0) = .1, p(1) = .15, p(2) = .2, p(3) = .25, p(4) = .2, p(5) = .06, and p(6) = .04. first, construct the probability distribution table and derive the cumulative distribution function and use both the answer the following questions. question 8: probability that between 2 and 5 lines, inclusive, are not in use.

Step-by-step explanation:

Given that  X denote the number of telephone lines in use at an online business.

The variable x can take values from 0 to 6 and the probability can be tabulated as follows:  Cumulative probability is the Prob =P(X<=x)

We want prob that between 2 and 5 lines, inclusive not in use

This is equivalent to

1-

=

2

step-by-step explanation:

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)