An engineering school reports that 53% of its students were male (m), 35% of its students were between the ages of 18 and 20 (a), and that 21% were both male and between the ages of 18 and 20. what is the probability of choosing a random student who is a female or between the ages of 18 and 20? assume p(f) = p(not m). your answer should be given to two decimal places.

Our required probability is 0.65.

Step-by-step explanation:

Since we have given that

                      18-20                  Not 18-20           Total

Male                0.23                    0.35                 0.58

Female            0.16                     0.26                0.42

Total                0.39                    0.61                   1

P(female or between 18-20) = P(female) + P(18-20) - P(Female and 18-20)

P(female or between 18-20) =  0.42+0.39-0.16

P(female or between 18-20) = 0.65

Hence, our required probability is 0.65.

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

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