Write the equation of a line that is perpendicular to the given line and that passes through the given point.
-3x - 5y = 17; (6, 3)
y=2x-9
y = 2x - 9
y = -2x - 9
y = 2x + 0

y - 3 = (5/3)(x - 6)

Step-by-step explanation:

The usual first step is to determine the slope of the given line.

In this case the slope is -3/5.

A line perpendicular to this given line would have a slope of 5/3, which is the negative reciprocal of -3/5.

This new line goes thru (6, 3) and has a slope of 5/3.  Thus, the equation of the line in point-slope form is

y - 3 = (5/3)(x - 6)

Double check that you have copied the problem down correctly.  The slope of the line represented by -3x - 5y = 17 is neither 2 nor -2; it is -3/5, and so the slope of a line perpendicular to -3x - 5y = 17 is +5/3.

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).