Achild bounces a 48 g superball on the sidewalk. the velocity change of the super bowl is from 23 m/s downward to 14 m/s upward. if the contact time with the sidewalk is 1800 s, what is the magnitude of the average force exerted on the superball by the sidewalk?

= 0.0009866 N

Step-by-step explanation:

For resolving this problem we can use the impulse-momentum theorem; this theorem establishes that  the change in momentum of an object equals the impulse applied to it

The impulse is defined how:

I = Δt

    :   Average force

    Δt =  Time interval

Then:

Δt

(0.048)(14) - (0.048)(-23) = (1800)

0.672 + 1.104 = 1800

1.776 = 1800

=

= 0.0009866 N

29 mil

step-by-step explanation: