What were the dimensions of the original photo?
miriam reduced a square photo by cutting 3 inches away
from the length and the width so it will fit in her photo album.
the area of the reduced photo is 64 square inches. in the
equation (x-3) = 64, x represents the side measure of the
original photo.
11 inches by 11 inches
5 inches by 5 inches
o
3 + 4/2 inches by 3 + 4/2 inches
o 3 - 42 inches by 3 - 42 inches

A. 11 inches by 11 inches

Step-by-step explanation:

We have been given an equation , where x represents the side measure of the  original photo. The equation represents the area the area of the reduced photo. We are asked to find the dimensions of the original photo.

Let us solve for x by taking positive square root of both sides.

Add 3 on both sides:

Therefore, the dimensions of the original photo are 11 inches by 11 inches and option A is the correct choice.

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.