Write each equation in slope-intercept form of the equation of a line. underline the slope and circle the y-intercept in each equation.

3x+4y–12=0

2x+y=1

2x–y=0

A) slope of equation 3x+4y-12=0 is m= and y-intercept is 3

B) slope of equation 2x+y=1 is m=-2 and y-intercept is 1.

C) slope of equation 2x-y=0 is m=2 and y-intercept is 0.

Solution:

The slope - intercept form equation of line is given as

y=mx+c  --- eqn (1)

Where m is the slope of the line. The coefficient of “x” is the value of slope of the line.

c is the y – intercept which is the value of y at the point where the line crosses the y-axis

a) Given that

3x+4y-12=0    --- eqn (2)

On converting equation (2) in slope intercept form, we get

4y=-3x+12

On comparing equation (3) and (1) we get slope of equation (2) is   and y-intercept is 3.

b)  Given that

2x+y=1           …(4)

On converting equation (2) in slope intercept form, we get

y=-2x+1       …(5)

On comparing equation (5) and (1) we get slope of equation (4) is m=-2 and y-intercept is 1.

C)Given that

2x-y=0           …(6)

On converting equation (6) in slope intercept form, we get

y=2x              …(7)

On comparing equation (7) and (1) we get slope of equation (6) is m=2 and y-intercept is 0.

$12. that is my answer.