Mathematics, 08.10.2019 20:30, mom2acjm

Solve to get to x 2x + 1 = 2(x -10)

Answers: 1

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answered: catman7884

x=5

Step-by-step explanation:

Subtract

from both sides of the equation.

√

−

To remove the radical on the left side of the equation, square both sides of the equation.

(

√

−

)

(

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)

Simplify the left side of the equation.

−

(

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)

Simplify the right side of the equation.

Tap for more steps...

−

Since

is on the right side of the equation, switch the sides so it is on the left side of the equation.

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Move all terms containing

to the left side of the equation.

Tap for more steps...

−

Move

to the left side of the equation by adding it to both sides.

−

Add

and

−

Factor

−

using the AC method.

Tap for more steps...

(

−

)

(

−

)

Set

−

equal to

and solve for

Tap for more steps...

Set

−

equal to

and solve for

Tap for more steps...

The solution is the result of

−

and

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Exclude the solutions that do not make

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−

true.

5Subtract

from both sides of the equation.

√

−

To remove the radical on the left side of the equation, square both sides of the equation.

(

√

−

)

(

−

)

Simplify the left side of the equation.

−

(

−

)

Simplify the right side of the equation.

Tap for more steps...

−

Since

is on the right side of the equation, switch the sides so it is on the left side of the equation.

−

Move all terms containing

to the left side of the equation.

Tap for more steps...

−

Move

to the left side of the equation by adding it to both sides.

−

Add

and

−

Factor

−

using the AC method.

Tap for more steps...

(

−

)

(

−

)

Set

−

equal to

and solve for

Tap for more steps...

Set

−

equal to

and solve for

Tap for more steps...

The solution is the result of

−

and

−

Exclude the solutions that do not make

√

−

true.

answered: Guest

the correct answer is 828.07

answered: Guest

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

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