98 points and brainliest

find a quadratic function that includes the set of values below

(0,,,0)

y=-4x^2+9x+9

Step-by-step explanation:

1st: we assume the equation will be in standard form (ax^2+bx+c)

2nd: since the graph passes through (0,9) then the y-intercept is @(0,9) or your c is 9.

3rd: since it passes through (2,11) then 11=4a+2b+c

4th: since it also passes through (3,0) then 0=9a+3b+c

* so we have c=9, 11= 4a+2b+c, and 0= 9a+3b+c*

So a=-4, b=9, c=9

plug in the numbers and you get y= 4x^2+9x+9

Hope this helps you. :3

a

step-by-step explanation:

true

step-by-step explanation:

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