An oil exploration firm is formed with enough capital to finance ten explorations. the probabil- ity of a particular exploration being successful is .1. assume the explorations are independent. find the mean and variance of the number of successful explorations.

μ = 1 The firm expects that one oil exploration will be successful.

v(x)= 0.9

Step-by-step explanation:

The first step is to define the random variable x as:

x: number of oil explorations being succesful

Then x can be take this values:

x = 0 , x =1 ... x =10

x is a binomially distributed random variable with parameters.

p = 0.1 and  n=10

And the mean or the expected value of x is:

μ = E(x) = np

Then μ = 10*0.1 = 1

And the variance of x is:

V(x) = np(1-p)

V(x) = 10(0.1)(1-0.1)= 0.9

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)