Mathematics, 08.10.2019 02:30, starreee
Write and equation for the line in point-slope form that passes through (2,-5) and is perpendicular to the line 2x-4y+8=0
Answers: 2
![\bf 2x-4y+8=0\implies -4y=-2x-8\implies y = \cfrac{-2x-8}{-4} \\\\\\ y = \cfrac{-2x}{4}-\cfrac{8}{-4}\implies y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{1}{2}}x+2\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill](/tpl/images/0298/9597/dc1d1.png)
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Write and equation for the line in point-slope form that passes through (2,-5) and is perpendicular...
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